y^2+0.2y+0.01-36y^2=0

Solution for y^2+0.2y+0.01-36y^2=0 equation:

y^2+0.2y+0.01-36y^2=0

We add all the numbers together, and all the variables

-35y^2+0.2y+0.01=0

a = -35; b = 0.2; c = +0.01;
Δ = b2-4ac
Δ = 0.22-4·(-35)·0.01
Δ = 1.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.2)-\sqrt{1.44}}{2*-35}=\frac{-0.2-\sqrt{1.44}}{-70}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.2)+\sqrt{1.44}}{2*-35}=\frac{-0.2+\sqrt{1.44}}{-70}
$